$\left(2x^3y^{-\frac{1}{4}}\right)^2\left(8y^{-\frac{3}{2}}\right)^{-\frac{1}{3}}$
$1^2-4\cdot1+3$
$\left(9x-5\right)\left(9x+5\right)$
$3x+6\le27$
$3+6\:-\:9\:-\:8\:-\:7+3\:-\:2$
$-a^2b+3\:11\:a^3b$
$\left(12m^3ab^6+4y\right)\left(12m^3ab^6-4y\right)$
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