$f\left(x\right)=in\left(t^2\left(3t^2+6\right)\right)$
$\left(2x^2-2x\right)^3$
$\left(x-10\right)\left(-6x^2+x+5\right)$
$4x+20x+25c$
$5x+40$
$1\le\frac{1}{1-x^2}$
$\left(a^x-a^{x+1}+a^{x+2}\right)\left(a^2+1\right)$
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