$\sqrt[3]{10^2+4\cdot29}$
$4b^2-16$
$\frac{x^2+10x+24}{x+6}$
$\int\sec\frac{1}{2}xdx$
$\frac{ax^2+b\sqrt{x^3}+c\sqrt[7]{x^3}}{x}$
$\int_0^x\left(x^2\right)dx$
$\left(\sqrt{1-x}\right)^4$
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