$\lim_{x\to\infty}\left(\frac{2x-1}{x+1}\right)$
$\int\frac{x-arctg4x}{1+16x^2}dx$
$0^{47}$
$\int\frac{9x^2+x-4}{x^3-x}dx$
$\lim_{x\to-7}\left|x\right|$
$2x^2+8x-1=0$
$x^2+4y^2+9z^2=0$
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