$\frac{dy}{dx}=\frac{4}{y^2e^{2x}}$
$\frac{2-2x}{x}\ge6$
$\frac{1}{2}log36-log3+3logx$
$4x-13\le2x+15$
$\frac{dy}{dx}\left(\frac{3}{y}+2x\right)$
$5b^2+\:42b\:+\:49$
$t^2\cdot\frac{dx}{dt}+5tx=t^3\cdot ln\left(t\right)+4$
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