$x-\frac{5}{3}\ge\frac{5\left(1-x\right)}{4}$
$\frac{3x^3}{-4x^4}$
$\lim_{x\to0}tan9xln4x$
$2tan\left(x\right)^2\:+2\:$
$\left[12+\left(5-9\right).4\right]$
$10x^4-25x^2+15x$
$\frac{y^3z^6}{y^5z^4}$
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