$16mn^2\:+\:14\:m^3n^3\:-\:4n^4$
$x^3-21x^2147x-343$
$\left(x^2+6x^2-4x+7\right)-\left(3x^2+2\cdot x-4\right)$
$\:\frac{\left(\left(x+12\right)\cdot\left(4x+12\right)\right)}{12}=180$
$\left(3n-m\right)^3$
$3^0+3^{-2}$
$\sin x\sin4x$
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