$\frac{2}{x+5}-\frac{x}{x-5}=1$

$5-8x>-3$

$\frac{1}{4}\sin\left(4x\right)=\sin\left(x\right)\cos^3\left(x\right)-\cos\left(x\right)\sin^3\left(x\right)$

$\left(x^2\:y^3\right)^{-7}$

$\arctan^{-1}\left(\frac{\sqrt{2}}{2}\right)+\tan^{-1}\left(\frac{\sqrt{3}}{2}\right)]-\frac{\pi}{6}$

$10a^2b^3c.\left(11ba-12\:-8a^3b^4\right)$

$\int x^3\sqrt{x+7}dx$