$\frac{dx}{dy}=\frac{1}{2x}$
$4x^2+8x-3=0$
$4\log\left(x\right)-3\log\left(x^2+1\right)+5\log\left(x-1\right)$
$\frac{dy}{dx}=\frac{1-y}{x-1}$
$-8,8=-2,4+\frac{w}{4}$
$\int12\left(tan^5x\right)\left(sec^2x\right)dx$
$\int x\cdot e^{-0.01x^2}dx$
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