$\frac{3\cdot10^4}{8\cdot10}$
$\int\left(1+\frac{1}{u}\right)^3\left(\frac{1}{u}\right)du$
$\frac{du}{dt}=\left(1+u\right)\left(8+t\right)$
$\int\frac{\left(ln\left(x\right)\right)^{44}}{x}dx$
$\frac{dy}{dx}=\left(6x^3-3x^2+30x-15\right)$
$\frac{-24x+7}{5}\le3$
$\frac{-x}{x}$
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