$-2\left(\frac{1}{4}m^5\right)\left(n^3\right)$
$\frac{dn}{dt}=0.25n\left(10-n\right)$
$u^2-15u+14$
$8-3c=8+2c$
$\left(3a^4+15b^2\right)$
$\lim_{n\to\infty\sqrt{n^2+1}}-n$
$-3ab\cdot8a^3b$
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