$a-4b+5ac;\:a=1;\:b=-2y;c=3$
$\lim_{x\to\infty}\left(\frac{x^3-3x}{x-2}\right)$
$\lim_{x\to0}\left(\frac{\sin^2\left(180x\right)}{\pi x^2}\right)$
$16a+24b\:$
$4x^2<1$
$\frac{dy}{dx}=2-\frac{3y}{100+2x}$
$a^2b^2-3ab^2$
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