$\left(k+1\right)^2$
$9x^{-7}-6x^{-8}$
$10-\left(-7+5\right)$
$-5a^2b^2\left(3b-5b+16\right)$
$\lim_{x\to\infty}e^{-x^2}\ln\left(x\right)$
$\frac{x+6}{2}\le\frac{5-x}{4}$
$-\left(-23\right)+\left(-67\right)+\left|-14-\left(-22+12\right)-\left(-11\right)\right|-\left(-2\right)$
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