$b^2x^2-9b^2$
$sin\left(x\right)^2=\sin\left(x\right)^2+\cos\left(x\right)^4$
$3\sqrt{64}$
$\cos\left(x\right)+0.5=0$
$2sin^2x-1=sin^{2x}-cos^2x$
$6^{3x-4}=36^{2x+4}$
$4x^2-40x+1$
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