$\lim_{x\to\infty}\left(\frac{ln\left(x-1\right)}{ln\left(x-1\right)}\right)^x$

$\left(1+\tan^2\left(x\right)\right)\left(1-\tan^2\left(x\right)\right)$

$.125m+.25=\frac{1}{2}$

$\frac{x^4-x^3+2x^2-x+2}{x+1}$

$\frac{2x^5+55x^2}{x+3}$

$\lim_{x\to1}\left(\frac{x-1}{sin\left(x\right)}\right)$

$x^2+c=0$