$\frac{dy}{dt}=t^{\frac{3}{2}}y^5$
$\left(-3x^2y^5+6x^4y^4\right)^2$
$\frac{343-125}{7-5}$
$x^22x+50$
$2p^3q\:+\:2p^2q^2\:+\:2pq^3\:$
$\sqrt[3]{6x^3}y^2\cdot\sqrt[3]{2x^2y^5}$
$0.4x^2y-0.7xy^2+1.2x^2y-2.4x^2y-0.2xy^2$
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