$7x^4+2y\:+\:3x^5-y$
$x^2-8x\:+\:6\:=\:0$
$\frac{1}{x+1}-\frac{1}{x+2}=\frac{1}{6}$
$x\frac{dy}{dx}-3y=x^3$
$\sqrt{x}+\sqrt{x+7\:}=7$
$\left(-2.-2+12\right)+1$
$4x^3-x^2y-x+5y=0$
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