$\int_1^{\infty}\frac{1}{1+16x^2}dx$

$3x-2\left(x+1\right)=19$

$\left(\frac{2}{3}x^4-\frac{3}{5}x^3\right)\left(\frac{2}{3}x^4+\frac{3}{5}x^3\right)$

$\lim_{x\to0}\left(\frac{x\:arcsen\left(x\right)}{sen\left(x\right)\:cos\left(x\right)}\right)$

$3\left(c\:-9\right)\:-\:7\left(c\:+1\right)\:+\:2\left(c\:+\:4\right)$

$x^2\:-\:12\:\le0$

$\left(-2yx^3\right)^2$