$\int\frac{\left(6e^x+9e^{-x}\right)}{\left(6e^x-9e^{-x}\right)}dx$
$\left(1.3ax\right).\left(1+3ar\right)$
$20 - 5 \cdot 4$
$\left(37u^3-15u-8u^2-20u^5\right)+\left(4u^2-5\right)$
$-5a-a$
$2x^4-2x^3+6x^2$
$\left(ac+ad\right)^2$
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