$\lim_{x\to\infty}\left(1+\frac{1}{x}\right)^5$
$-3x^2y+2x^2$
$27\:x^3-y^3$
$\frac{dx}{dy}+\frac{4x}{y}=y^2-1$
$\sec\left(x\right)+\csc\left(x\right)\left(\cos\left(x\right)-\sin\left(x\right)\right)$
$\left(2^3\cdot3^2\right)\left(2^{-2}\cdot5^4\right)$
$9x-4=8x+3$
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