$x+4=3$
$\int bxdx$
$3x^2-9x-3x^2+20x$
$12-\left(24-\left(-12\right)+\left(-8\right)+18\right)$
$\frac{2a\left(3a-4b\right)}{a}$
$4\left(x^2-3x+2\right)>0$
$\frac{4x^{4}+9x^{3}+6x^{5}-1}{x+2x^{3}-1}$
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