$6x-4\left(2x+8\right)=16$
$\left(5\cdot8-2\right)\cdot3$
$7a^2+5ab$
$\frac{3}{4}^{-3}$
$t^2+144+122t$
$\left(6x+7\right)\left(2+x\right)$
$\sqrt{9\cdot a^3\cdot b^6\cdot c}$
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