$-4\left(9+6\right)$
$y^'+\frac{2}{x}y=xe^x$
$\frac{38x^4-65x^3+27}{2x^2-5x+3}$
$-2\left(-1\right)^2+3\left(-1\right)$
$y=\sin\left(4x-2\right)$
$laplace\left(t^3\cos\:\left(t\right)\right)$
$\left(3a^3\right)^3$
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