$\lim_{x\to\infty}\left(\frac{3x^2-4x}{2x-3}\right)$
$a^{-\frac{3}{5}}$
$\sqrt{12x}+\sqrt{27x}+\sqrt{48x}$
$\left(x+y\right)\left(x-y\right)\left(x+y\right)$
$3x\left(-6x^2\right)\left(2x^3\right)$
$\sqrt{16a^8b^{-2}}$
$\sqrt[2]{9}-5$
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