$\sqrt[4]{x^8}y^3$
$\sqrt[3]{4ab^3}\sqrt[3]{16a^2}$
$b^2+26b+blank$
$\frac{dy}{dx}y=\pi^6$
$15+9-5\cdot2-6\cdot4\cdot3+5-4\cdot3-4$
$4x-8>16$
$3x-8y-2z\:+\:7x+3y+z$
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