$\frac{3}{5}a\:\:.\:\frac{5}{6}b$
$x^2-a^2+x-a^2$
$y^2-y-20=0$
$\frac{8}{x+4}=\frac{6}{x-7}$
$1x^4$
$\lim_{x\to1}\:\:\:x^2-1$
$\frac{\left(6x^5-5x^3+2x^2-3x+2\right)}{\left(2x^2+1\right)}$
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