$\frac{\left(2\right)}{\left(2-c\right)}>-4$

$\frac{2x^2-3}{x^2-2x-8}$

$\left(\frac{\sin\left(x\right)+\tan\left(x\right)}{\cos\left(x\right)+1}\right)+1$

$\sin\left(x\right)+\frac{1}{\sec\left(x\right)}=\sin\left(x\right)\csc\left(x\right)$

$\frac{8+27y^6}{2-3y^3}$

$-3-8-7$

$\frac{8x^3+27m^3n^6}{2x+3mn^2}$