$\frac{d}{dx}e^5$
$\frac{1-\sin\left(x\right)}{\cos\left(x\right)}=\frac{1+\sin\left(x\right)}{\cos\left(x\right)}$
$\left(4x^2+8y^3\:\right)\left(4x^2-8y^3\:\right)$
$x^8+y^7=2$
$7^{-4}\cdot7^3$
$\int\frac{7x+7}{x^2+1}\:dx$
$x-3y=4$
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