$\frac{2^2}{3}\:+\:\frac{2^3}{3}$
$6\cos x+3=0$
$\frac{m^2-9}{5m^2-5m}$
$\lim_{x\to\infty}\:\sqrt[x]{2}$
$x^2+4x+5<0$
$x^2-4\ge2x+4$
$\lim_{x\to\infty}\frac{1}{2^{\sqrt{x}}}$
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