$11x\left(5y+4z-7w\right)$
$y'+y=5x$
$\left(4x^2+16x+64+\frac{256}{x-4}\right)\left(x-4\right)\left(x^2+4x+16\right)$
$\frac{6^{-3}}{6^{-4}}$
$\frac{3x^2}{-9x^5}$
$\frac{\left(4a^3-8a^2b\right)}{\left(3a^2x-6abx\right)}$
$\int\left(2x^2\left(4x^3-1\right)^3\right)dx$
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