$1-5-6$
$\left(-1\right)^9$
$xy=x^2+x+y$
$\lim_{x\to\left(0\right)}\left(\frac{ln\left(cos\left(2x\right)\right)}{ln\left(cos\left(3x\right)\right)}\right)$
$\frac{10x^5}{2x^3}$
$4ab+6ab$
$f\left(x\right)=\frac{1x^2}{4}$
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