$p^2-6p-40=0$
$-9x^{5}y^{5}\left(3x^{4}y\right)$
$\frac{18x}{5}=36$
$\frac{6x}{3-x}\le2$
$8^{6}\cdot8^{-2}$
$\left(x-2\right)\left(x^2+3x\right)\left(2x\right)$
$\lim_{x\to0}\left(\frac{5}{x}-\frac{5}{\sin\left(x\right)}\right)$
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