$-6x^2-40x-75$
$\lim_{x\to-3}\frac{x^3-9x}{x^2-3x}$
$\int\left(\sqrt[3]{\left(5x^3+3\right)}x^2\right)dx$
$\frac{10x^2+3x^3+11x+6}{x+2}$
$5a^2+2bc+3d=10$
$7x-6y=30$
$\int\frac{5x^2+5x-4}{\left(x+2\right)\left(x+1\right)\left(x^2+x+1\right)}dx$
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