$\left(n^2-1\right)^2\left(n^2+7\right)\left(n^4-6n^2+7\right)$
$4a^2b\cdot5a^3b^4-2a^4b^5$
$1\left(3-x\right)-1\left(x+2\right)$
$-36+x<8$
$\left(x^{a-1}-1\right)^2$
$\lim_{x\to3}\left(\frac{2x-\sqrt{48-4x}}{2x^2+x-15}\right)$
$\sqrt[3]{2+6}-2$
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