$\lim_{x\to1}\left(\frac{8-\sqrt[3]{64+x}}{\sqrt[3]{64+x}-4}\right)$

$\left(-2+5\cdot3\right)-4\cdot4$

$\left(4x+3\right)\left(2x+3\right)\left(x+1\right)$

$\frac{\left(-2\sqrt[4]{\frac{\pi}{2}}\right)}{\frac{\pi}{2}}$

$100k^2-43k^2$

$\frac{dy}{dx}=\frac{2y}{x};y\left(4\right)=5$

$\frac{dy}{\:dx}=e^{3x+2y}$