$x^2+\frac{4x}{3}+\frac{4}{3}$
$\frac{dy}{dx}\left(-\frac{3x}{4y}\right)$
$6-2x=10$
$\left(3+\cos\left(2x\right)\right)$
$3^5\:.\:2^3x^3$
$4x-8y+6x^2+3x-5y$
$\left(-13\cdot14\right)\cdot\left(\frac{20}{10}\right)$
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