$3\cdot\left(6-2\right)^2$
$\left(1-t^2\right)\frac{dx}{dt}+4tx=t$
$453\:+\:38,215\:$
$\frac{d}{dx}\cdot x^2+y^2=a^2$
$x^3+\frac{8}{x}-2$
$\left(2.80\right)\cdot\left(-30.6\right)$
$2z^6-1.6z^6+5.5z^6-1.4z^6$
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