$\lim_{x\to1}\left(\frac{x^{9a}-9ax+9a-1}{\left(x-1\right)^2}\right)$
$a^2+a^2b+a^2^2c$
$\frac{\left(4x+7\right)}{5x+8}=\frac{\left(11\right)}{14}$
$x^3+\frac{x^2}{2}-4x-2$
$\frac{x}{-2}=3$
$b+169=421$
$x^2-6x-11=0$
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