$y'=\frac{e^{6x}}{y^2},\:y\left(0\right)=2$
$\frac{y^7}{y-4}$
$\left(5+y\right)\left(12+y\right)$
$x^2y-xy$
$3x-12=x+36$
$\frac{1}{25}+\frac{25x^{4}}{36}-\frac{x^{2}}{6}$
$\left(1-x\right)^{cos\left(\frac{3.141592653589}{2}\right)}$
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