$x^{2\:}+19x+12=\left(4x+3\right)\left(x+4\right)$
$x-5>3x$
$7m^2-m^2+3n-\left(5-n\right)-\left(-3+m^2\right)-\left(2n+3\right)$
$x^2+9+16$
$\left(-4y+5z\right)\left(-3z+2y\right)$
$4x^2-6x=0$
$sin\left(2x\right)\left(cos\left(2x\right)\:+1\right)=0$
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