$\frac{y}{x^3}=1$
$tan\left(x\right)csc^2\left(x\right)-\tan\left(x\right)=\cot\left(x\right)$
$\int\frac{x}{\left(5x+3\right)^3}dx$
$\frac{dy}{dx}+2x=14$
$80^2-20^2$
$x+4x+8$
$\left(a^2+3-a\right)\:\left(a^2+3-a\right)$
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