$\left(2x-3\right)\left(2x+3\right)+2\left(x-2\right)\left(x-3\right)$
$\left(a^2c^3\right)\left(ac^2\right)$
$\frac{dy}{dx}=\frac{2x-1}{y^2}$
$76+4$
$-4x^5+24x^4-40x^3-8x^2+64x-32$
$\frac{1}{1+cos\left(x\right)}=8$
$y=3x^3+4x-3y$
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