$\sqrt[3]{81x^3y^4}$
$x^2-32x+256=0$
$\frac{dx}{dy}+x^2=x$
$2\left(-3\right)-\left(-15\right)$
$\int\frac{x^5}{\sqrt{9-x^2}}dx$
$\frac{dy^{'y}}{dx^{'y}}+8x=0$
$\frac{\left(x^2+6\right)}{x^2-1x}$
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