$\lim_{x\to2}\frac{8x^3-64}{2x-4}$
$2u^2-u-1=0$
$25x^4y^2-121$
$\frac{d}{dx}2x^3-y^2=xy$
$\log\left(\frac{6\left(x+4\right)^3}{\sqrt{x^5}}\right)$
$\int_{-\infty}^{-1}\left(\frac{3}{\sqrt{5-x}}\right)dx$
$-8x^{-4}y^{\frac{1}{2}}$
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