$\int\frac{-1}{\left(4u+3\right)^3}du$
$64x^2+144xy^2+81y^4$
$\frac{3}{2x+4}+\frac{x+1}{2x-4}+\frac{x+8}{x^2-4}$
$=\left(+7\right)\left(+5\right)\left(-3\right)$
$\left(a^{12}\right)^{-6}$
$sen\left(\frac{\pi\:}{2}+\frac{\pi\:}{6}\right)$
$\lim_{x\to8}\frac{\sqrt[2]{x+1}-3}{\sqrt[3]{x\:}-2}$
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