$16x^2+8x+1=0$

$\left(-1\right)^2-3\left(-1\right)+1$

$\lim_{x\to0}\left(\sec\left(x\right)-\tan\left(x\right)\right)$

$-1<\frac{n+10}{6}$

$( 3 x ^ { 2 } + 2 x ) ( 2 x - 2 )$

$\lim_{x\to2}\frac{x^4-4x^3+4x^2}{x-2}$

$\lim_{x\to0}\left(\frac{\arcsin\left(\sqrt{x+1}-\sqrt{\cos\left(x\right)}\right)}{\tan\left(x\right)}\right)$