$\frac{dx}{dy}=\frac{-\left(x+x.\:\cos\:\left(x.y\right)\right)}{y+y.\cos\left(x.y\right)}$

$\frac{d}{dx}\ln\sqrt[3]{x^3+8}$

$36\left(m+n\right)^4-121\left(m-n\right)^4$

$3^{\left(x^2+8\right)}=9^{3x}$

$\frac{d}{dx}\left(arctan\left(4e^{-7x}\right)\right)$

$\frac{d}{dx}+\frac{1}{3}y=\frac{4}{3}$

$\frac{1}{2}x-3\le-\frac{2}{3}x+\frac{5}{6}$