$-y+2y-5+7+7x^2-6x^2+3$
$\int x^2\left(5x+5\right)^-5dx$
$\int_{-\infty}^5\left(\frac{1}{x^3}\right)dx$
$\left(\sqrt{x}\right)\left(\sqrt{x}\right)$
$\frac{\left(x^3-10x^2+26x-5\right)}{\left(x-5\right)}$
$5x+3>3x-2$
$\frac{1-\text{tg}^2a}{1+\text{tg}^2a}=1-2\text{sen}^2a$
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