$1+2x-24x$
$-\left(6-\left(-4\right)\cdot\left(-9\right)\right)$
$\frac{d^2}{dx^2}\left(\frac{x}{x-1}^3\right)$
$\frac{a^6}{a^5}$
$\frac{2x^3-4x^2-2x+3}{-3}$
$3<2x-1$
$i x ^ { 2 } - x y + x ^ { 3 } - 8 = 0$
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