$\int\left(8x^{2}-3x+2\right)\left(2x-3\right)dx$

$\frac{2-x}{x+3}>-2$

$x+2y+-4y+6x+2x$

$\frac{dy}{dx}=\frac{y^3}{\sqrt{x^2+5x+6}}$

$\int-8\sin\left(\sqrt{x}\right)dx$

$\frac{dy}{dx}=\frac{1}{\sin\left(x\right)}$

$\lim_{x\to0}\left(\frac{1-\cos\left(5x\right)}{2x}\right)$